Exact Probability Test 
                 | 
              |||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
                  Fisher Exact Test | 
              |||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
| 
                   
 
 
 
 
 
 
                     Combination 0 
 
                     Probability of this combination occurring is 
                     Combination 1 
 
                     Probability of this combination occurring is 
                     Combination 2 
 
                     Probability of this combination occurring is 
                     Combination 3 
 
                     Probability of this combination occurring is 
                     Combination 4 
 
                     Probability of this combination occurring is 
                     Combination 5 
 
                     Probability of this combination occurring is 
                     We manually map out the whole probability space for men on a diet 
                     
 
                     
                     Is our particular combination significant? Are men different than women on a diet? Our data is P 2. If we choose an alpha of 5%, the best we can do in our case is to have an alpha of 11%. We take the probability that is in the tails. Alpha is the sum of P 0, P 1, and P 5. Since our value is P 2, we fail to reject and conclude men do not differ from women on a diet.  |